Optimal. Leaf size=53 \[ -\frac{(a+3 b) \tanh ^{-1}(\cos (e+f x))}{2 f}-\frac{(a+b) \cot (e+f x) \csc (e+f x)}{2 f}+\frac{b \sec (e+f x)}{f} \]
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Rubi [A] time = 0.0522348, antiderivative size = 53, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {4133, 456, 453, 206} \[ -\frac{(a+3 b) \tanh ^{-1}(\cos (e+f x))}{2 f}-\frac{(a+b) \cot (e+f x) \csc (e+f x)}{2 f}+\frac{b \sec (e+f x)}{f} \]
Antiderivative was successfully verified.
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Rule 4133
Rule 456
Rule 453
Rule 206
Rubi steps
\begin{align*} \int \csc ^3(e+f x) \left (a+b \sec ^2(e+f x)\right ) \, dx &=-\frac{\operatorname{Subst}\left (\int \frac{b+a x^2}{x^2 \left (1-x^2\right )^2} \, dx,x,\cos (e+f x)\right )}{f}\\ &=-\frac{(a+b) \cot (e+f x) \csc (e+f x)}{2 f}+\frac{\operatorname{Subst}\left (\int \frac{-2 b-(a+b) x^2}{x^2 \left (1-x^2\right )} \, dx,x,\cos (e+f x)\right )}{2 f}\\ &=-\frac{(a+b) \cot (e+f x) \csc (e+f x)}{2 f}+\frac{b \sec (e+f x)}{f}-\frac{(a+3 b) \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\cos (e+f x)\right )}{2 f}\\ &=-\frac{(a+3 b) \tanh ^{-1}(\cos (e+f x))}{2 f}-\frac{(a+b) \cot (e+f x) \csc (e+f x)}{2 f}+\frac{b \sec (e+f x)}{f}\\ \end{align*}
Mathematica [B] time = 0.387665, size = 236, normalized size = 4.45 \[ -\frac{a \csc ^2\left (\frac{1}{2} (e+f x)\right )}{8 f}+\frac{a \sec ^2\left (\frac{1}{2} (e+f x)\right )}{8 f}+\frac{a \log \left (\sin \left (\frac{1}{2} (e+f x)\right )\right )}{2 f}-\frac{a \log \left (\cos \left (\frac{1}{2} (e+f x)\right )\right )}{2 f}-\frac{b \csc ^2\left (\frac{1}{2} (e+f x)\right )}{8 f}+\frac{b \sec ^2\left (\frac{1}{2} (e+f x)\right )}{8 f}+\frac{3 b \log \left (\sin \left (\frac{1}{2} (e+f x)\right )\right )}{2 f}-\frac{3 b \log \left (\cos \left (\frac{1}{2} (e+f x)\right )\right )}{2 f}+\frac{b \sin \left (\frac{1}{2} (e+f x)\right )}{f \left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right )}-\frac{b \sin \left (\frac{1}{2} (e+f x)\right )}{f \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.05, size = 100, normalized size = 1.9 \begin{align*} -{\frac{a\csc \left ( fx+e \right ) \cot \left ( fx+e \right ) }{2\,f}}+{\frac{a\ln \left ( \csc \left ( fx+e \right ) -\cot \left ( fx+e \right ) \right ) }{2\,f}}-{\frac{b}{2\,f \left ( \sin \left ( fx+e \right ) \right ) ^{2}\cos \left ( fx+e \right ) }}+{\frac{3\,b}{2\,f\cos \left ( fx+e \right ) }}+{\frac{3\,b\ln \left ( \csc \left ( fx+e \right ) -\cot \left ( fx+e \right ) \right ) }{2\,f}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.01338, size = 103, normalized size = 1.94 \begin{align*} -\frac{{\left (a + 3 \, b\right )} \log \left (\cos \left (f x + e\right ) + 1\right ) -{\left (a + 3 \, b\right )} \log \left (\cos \left (f x + e\right ) - 1\right ) - \frac{2 \,{\left ({\left (a + 3 \, b\right )} \cos \left (f x + e\right )^{2} - 2 \, b\right )}}{\cos \left (f x + e\right )^{3} - \cos \left (f x + e\right )}}{4 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 0.815347, size = 325, normalized size = 6.13 \begin{align*} \frac{2 \,{\left (a + 3 \, b\right )} \cos \left (f x + e\right )^{2} -{\left ({\left (a + 3 \, b\right )} \cos \left (f x + e\right )^{3} -{\left (a + 3 \, b\right )} \cos \left (f x + e\right )\right )} \log \left (\frac{1}{2} \, \cos \left (f x + e\right ) + \frac{1}{2}\right ) +{\left ({\left (a + 3 \, b\right )} \cos \left (f x + e\right )^{3} -{\left (a + 3 \, b\right )} \cos \left (f x + e\right )\right )} \log \left (-\frac{1}{2} \, \cos \left (f x + e\right ) + \frac{1}{2}\right ) - 4 \, b}{4 \,{\left (f \cos \left (f x + e\right )^{3} - f \cos \left (f x + e\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.26612, size = 278, normalized size = 5.25 \begin{align*} \frac{2 \,{\left (a + 3 \, b\right )} \log \left (-\frac{\cos \left (f x + e\right ) - 1}{\cos \left (f x + e\right ) + 1}\right ) - \frac{a{\left (\cos \left (f x + e\right ) - 1\right )}}{\cos \left (f x + e\right ) + 1} - \frac{b{\left (\cos \left (f x + e\right ) - 1\right )}}{\cos \left (f x + e\right ) + 1} + \frac{a + b + \frac{14 \, b{\left (\cos \left (f x + e\right ) - 1\right )}}{\cos \left (f x + e\right ) + 1} - \frac{a{\left (\cos \left (f x + e\right ) - 1\right )}^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} - \frac{3 \, b{\left (\cos \left (f x + e\right ) - 1\right )}^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}}}{\frac{\cos \left (f x + e\right ) - 1}{\cos \left (f x + e\right ) + 1} + \frac{{\left (\cos \left (f x + e\right ) - 1\right )}^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}}}}{8 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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